How to write a program in C++ that reads a set of integers and finds and prints the sum of the even and odd #.

just do interger division





if (number%2 %26gt; 0)


{


odd = odd + number;


}


else


{


even = even + number;


}





what % does is give you a remainder when doing interger division, the number has to be of type int. so if the number divides evenly by 2 then the remainder is 0. so we know it's even, if you divide 3 by two the % will equal 1, so we know the number is odd, etc... hmm might not work for 1, so make if read:





if (number%2 %26gt; 0 || number == 1)





so cut and paste this into a compiler:





#include %26lt;iostream%26gt;





int main()


{


using namespace std;





int number, even(0), odd(0);





do


{


cout %26lt;%26lt; "Please enter a number %26lt;Enter 0 to end input%26gt;: ";


cin %26gt;%26gt; number;





if (number%2 %26gt; 0 || number ==1)


odd = odd + number;


else


even = even + number;


}while (number != 0);





cout %26lt;%26lt; "The sum of the odd numbers entered is " %26lt;%26lt; odd %26lt;%26lt; endl;


cout %26lt;%26lt; "The sum of the even numbers entered is " %26lt;%26lt; even %26lt;%26lt; endl;





system("pause");


return 0;


}





that was kinda of fun, enjoy (won't work for negative, you can do that part). you call always change this to read from a file as well, the rest is up to you, i already gave you too much.

How to write a program in C++ that reads a set of integers and finds and prints the sum of the even and odd #.
Doing your homework, eh?