hi, i have no idea how to do this, can someone help me with it?
given set S={1,{a,c},b,c} Find:
- all the subsets of S
- all the proper subsets of S
Thanks
Given set S={1,{a,c},b,c}?
Subset of s={ {1}, {a,c}, {b}, {c}, {1,(a,c)}, {1,b}, {1,c}, {(a,c),b},{(a,c),c}, {b,c}, {1,(a,c),b}, {1,(a,c),c}, {(a,c),b,c}, {1,{a,c},b,c},{ } }
Proper subsets of S={ {1}, {a,c}, {b}, {c}, {1,(a,c)}, {1,b}, {1,c}, {(a,c),b},{(a,c),c}, {b,c}, {1,(a,c),b}, {1,(a,c),c}, {(a,c),b,c} }
Hei! Im not sure whether nullset is a proper subset or not
Reply:-subsets of S =%26gt; { },{1},{{a,b}},{b},{C}
- all the proper subsets of S
=%26gt;
{ }
{1,{a,c},b,c}
{1}
{1,{a,c}}
{1,c}
{1,b}
{1,{a,c},b}
{1,{a,c},c}
{1,b,c}
{{a,c}}
{{a,c},b}
{{a,c},c}
{{a,c},b,c}
{b}
{b,c}
{c}
{1,{a,c},b,c}
Reply:For a list of all the proper subsets of S, list all sets with 1 element , for example {1}, {{a,c}}, {b}, {c}
Now list all sets with 2 elements.
{1, {a,c} }, { 1, c } -- finish all combinations.
Now list all sets with 3 elements.
{1, {a,c} , b} -- finish all combinations.
Note that {a,c} is 1 element even though it is a set.
For a list of all subsets:
First list all proper subsets above.
Add the set : {1, {a,c}, b, c }
This original set is a subset of itself.
We also have the nullset Φ. But it is implied that the null set is a subset of every set and you can forget about it.
forsythia
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