My codes looks something like this:
ifstream infile
infile.open("hours.dat");
infile%26gt;%26gt;Records[i].....so on.
I want to be able to write:
cin%26gt;%26gt;Variable
infile.open(Variable);
infile%26gt;%26gt;Records[i].....
This isn't working for me. What am I doing wrong. Is it even possible to use a variable for a file name? How do I do it? Thanks!
C++: How do I set my file name as a variable so I can open whatever file I want during execution of program?
void open ( const char * filename, ios_base::openmode mode = ios_base::in );
Your file name must be of type const char *.
Your variable "Variable" must be a string since you are using
cin %26gt;%26gt; Variable;
So, to open the file, use:
infile.open(Variable.c_str());
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